Question

Write a balanced reaction for which the following rate relationships

            Rate = 1/2(∆[N2]/∆t) = (∆[O2]/∆t) = -1/2([N2O]/∆t)

Answer 1

Write a balanced reaction for which the following rate relationships

            Rate = 1/2(∆[N2]/∆t) = (∆[O2]/∆t) = -1/2([N2O]/∆t)

Look at the sign of the rate expression. It is negative with respect to N₂O. It indicates the concentration of N₂O decreases with time. Hence N₂O is the reactant. Positive value of rate with respect to both N₂ and O₂ indicates that concentration of N₂ and O₂ increases with time. Hence N₂ and O₂ are the products.

The reaction:

y N₂O = a N₂ + b O₂

Rate is expressed as: r = 1/a(∆[N2]/∆t) =1/b (∆[O2]/∆t) = -1/y([N2O]/∆t)

here, 1/a = 1/2

so, a = 2

1/b = 1

so, b = 1

-1/y = -1/2

so, y = 2

The equation is: 2N₂O = 2N₂ + O₂