Barium sulfate, BaSO4, is used in medical imaging of the gastrointestinal tract because it is opaque to X rays. A barium sulfate solution, sometimes called a cocktail, is ingested by the patient, whose stomach and intestines can then be visualized via X-ray imaging. If a patient ingests 200 mL of a saturated barium sulfate solution, how much toxic Ba2+ ion has the patient consumed?
The solubility product Ksp of BaSO4 is 1.10×10−10.
Express your answer to three significant figures and include the appropriate units.
Please help! Please show steps if possible! THANK YOU!!
Ksp = [Ba2+][SO42-]
1.1*10^-10=(s)*(s)
1.1*10^-10= 1(s)^2
s = 1.049*10^-5 M
This is molarity of BaSO4 saturated solution.
volume , V = 200 mL
= 0.2 L
use:
number of mol,
n = Molarity * Volume
= 1.049*10^-5*0.2
= 2.098*10^-6 mol
Mol of Ba2+ = mol of BaSO4
= 2.098*10^-6 mol
Molar mass of Ba = 137.3 g/mol
use:
mass of Ba2+,
m = number of mol * molar mass
= 2.098*10^-6 mol * 137.3 g/mol
= 2.881*10^-4 g
Answer: 2.88*10^-4 g
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