Question

Chlorine dioxide reacts in basic water to form chlorite and chlorate according to the following chemical equation:    2ClO₂(aq) + 2OH

Answer 1

From exp 1 an 2, it is clear that, the concentration of [OH-] is constant.

So, [ClO2]1 / [ClO2]2 = [Rate]1 / [Rate]2

[0.0500 / 0.100]^a = [5.75 x 10^-2] / [ 2.30 x 10^-1]

(0.5)^a = 0.25

a = 2

Thus, rate of the reaction with respect to [ClO2] is 2.

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FRom exp 2 and 3, it is clear that, the concentration of [ClO2] is constant.

So, [OH-]2 / [OH-]3 = [Rate]2 / [Rate]3

[0.100 / 0.0500]^b = [2.30 x 10^-1] / [ 1.15 x 10^-1]

(2)^b = 2

b = 1

Thus, rate of the reaction with respect to [OH-] is 1.

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Rate law = k [ClO2]^2 [OH-]