Question

When the chemical reaction: Br2(g) + Cl2(g) ↔ 2 BrCl(g) is at equilibrium, which answer describes two ways that the reaction would shift to the right?

Add Cl2 and add BrCl

Add Br2 and add BrCl

Remove Br2 and add Cl2

Add Br2 and remove BrCl

Remove Br2 and add BrCl

Answer 1

we know that

according to Le chatlier principle

the equilibrium will shift in a direction to counter the change

so

consider the reaction

Br2 + Cl2 --> 2 BrCl

now add Br2 and Cl2

now according to Le Chatlier principle

the equilibrium will shift in a direction to remove Br2 and Cl2

so

they will be consumed and BrCl is formed

that is the equilibrium is shifted to the right

similarly

remove Br2 and Cl2

the equilibrium will shift to the left

now

remove BrCl

so

according to Le Chatlier principle

the equilibrium will shift in a direction to add BrCl

so

more and more BrCl will be formed

so

the equilibrium will shift to the right

similarly add BrCl

the equilibrium will shift to the left

now

the requirement is the equilibrium should shift to the right

to

add Br2 or Cl2 or remove BrCl

so

the answer is

Add Br2 and remove BrCl