Question

Consider the gas-phase reaction, Cl2(g) + Br2(g) <=> 2 BrCl(g), for which Kp = 32 at...

Consider the gas-phase reaction, Cl2(g) + Br2(g) <=> 2 BrCl(g), for which Kp = 32 at 500 K. If the mixture is analyzed and found to contain 0.45 bar of Cl2, 0.65 bar of Br2 and 3.1 bar of BrCl, describe the situation:

1.

Q < K and more products will be made to reach equilibrium.

2.

Q < K and more reactants will be made to reach equilibrium.

3.

Within 1 decimal place, Q = K and the reaction is at equilibrium

4.

Q > K and more products will be made to reach equilibrium.

5.

Q > K and more reactants will be made to reach equilibrium.

Homework Answers

Answer #1

answer : 5. Q > K and more reactants will be made to reach equilibrium.

Cl2(g) + Br2(g) <=============> 2 BrCl(g)

0.45      0.65                                     3.1

Q = [BrCl]^2 / [Cl2][Br2]

    = 3.1^2 / 0.45 x 0.65

    = 32.85

Q = 32.86

Kp = 32

Q > K and more reactants will be made to reach equilibrium.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Consider the reaction: Br2(g)+Cl2(g)⇌2BrCl(g) Kp=1.11×10−4 at 150 K. A reaction mixture initially contains a Br2 partial...
Consider the reaction: Br2(g)+Cl2(g)⇌2BrCl(g) Kp=1.11×10−4 at 150 K. A reaction mixture initially contains a Br2 partial pressure of 785 torr and a Cl2 partial pressure of 725 torr at 150 K. Calculate the equilibrium partial pressure of BrCl.
Consider the reaction: Br2(g)+Cl2(g)⇌2BrCl(g) Kp=1.11×10−4 at 150 K. A reaction mixture initially contains a Br2 partial...
Consider the reaction: Br2(g)+Cl2(g)⇌2BrCl(g) Kp=1.11×10−4 at 150 K. A reaction mixture initially contains a Br2 partial pressure of 770 torr and a Cl2 partial pressure of 740 torr at 150 K. Part A : Calculate the equilibrium partial pressure of BrCl.
For the equilibrium Br2(g) + Cl2(g) ⇌ 2 BrCl(g) the equilibrium constant Kp is 7.0 at...
For the equilibrium Br2(g) + Cl2(g) ⇌ 2 BrCl(g) the equilibrium constant Kp is 7.0 at 400 K. If a cylinder is charged with BrCl(g) at an initial pressure of 1.00 atm and the system is allowed to come to equilibrium what is the final (equilibrium) pressure of BrCl? For the equilibrium  the equilibrium constant  is 7.0 at 400 . If a cylinder is charged with  at an initial pressure of 1.00  and the system is allowed to come to equilibrium what is the...
For the equilibrium Br2(g) + Cl2(g) ⇌ 2 BrCl(g) the equilibrium constant Kp is 7.0 at...
For the equilibrium Br2(g) + Cl2(g) ⇌ 2 BrCl(g) the equilibrium constant Kp is 7.0 at 400 K. If a cylinder is charged with BrCl(g) at an initial pressure of 1.00 atm and the system is allowed to come to equilibrium what is the final (equilibrium) pressure of BrCl? For the equilibrium the equilibrium constant is 7.0 at 400 . If a cylinder is charged with at an initial pressure of 1.00 and the system is allowed to come to...
For the equilibrium Br2(g) + Cl2(g) ⇌ 2 BrCl(g) the equilibrium constant Kp is 7.0 at...
For the equilibrium Br2(g) + Cl2(g) ⇌ 2 BrCl(g) the equilibrium constant Kp is 7.0 at 400 K. If a cylinder is charged with BrCl(g) at an initial pressure of 1.00 atm and the system is allowed to come to equilibrium what is the final (equilibrium) pressure of BrCl? For the equilibrium  the equilibrium constant  is 7.0 at 400 . If a cylinder is charged with  at an initial pressure of 1.00  and the system is allowed to come to equilibrium what is the...
If Kp=3.13x10-2 at 500 K for the reaction: Br2 (g) + Cl2 (g) <--> 2 BrCl...
If Kp=3.13x10-2 at 500 K for the reaction: Br2 (g) + Cl2 (g) <--> 2 BrCl (g) a) Calculate Kc at 500K b) What is the value of Kc for the reverse reaction at 500 K? c) Calculate the value of Kp for the following reaction at 500 K:    2Br2 (g) + 2Cl2 (g) <--> 4BrCl (g) d) Given the following two reactions and their equilibrium constants:    AgCl (s)<--> Ag+1 (aq) + Cl-1 (aq) Kc=1.8x10-10 M2    Ag+1...
When the chemical reaction: Br2(g) + Cl2(g) ↔ 2 BrCl(g) is at equilibrium, which answer describes...
When the chemical reaction: Br2(g) + Cl2(g) ↔ 2 BrCl(g) is at equilibrium, which answer describes two ways that the reaction would shift to the right? Add Cl2 and add BrCl Add Br2 and add BrCl Remove Br2 and add Cl2 Add Br2 and remove BrCl Remove Br2 and add BrCl
2 BrCl(g) ==== Br2(g) + Cl2(g) in which Kc = 0.145 at 25C. If the initial...
2 BrCl(g) ==== Br2(g) + Cl2(g) in which Kc = 0.145 at 25C. If the initial concentration of BrCl is 0.050 mol/L, calculate the equilibrium concentrations of Br2 and Cl2.  
Consider the reaction between iodine gas and chlorine gas to form iodine monochloride: I2(g)+Cl2(g)⇌2ICl(g)Kp=81.9 (at 298...
Consider the reaction between iodine gas and chlorine gas to form iodine monochloride: I2(g)+Cl2(g)⇌2ICl(g)Kp=81.9 (at 298 K) A reaction mixture at 298 K initially contains PI2=0.35 atm and PCl2=0.35 atm . What is the partial pressure of iodine monochloride when the reaction reaches equilibrium?
Consider the reaction between iodine gas and chlorine gas to form iodine monochloride: I2(g)+Cl2(g)⇌2ICl(g)Kp=81.9 (at 298...
Consider the reaction between iodine gas and chlorine gas to form iodine monochloride: I2(g)+Cl2(g)⇌2ICl(g)Kp=81.9 (at 298 K) A reaction mixture at 298 K initially contains PI2=0.40 atm and PCl2=0.40 atm . What is the partial pressure of iodine monochloride when the reaction reaches equilibrium?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT