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Consider the following reaction: CO2(g)+CCl4(g)⇌2 COCl2(g). Calculate ΔG for this reaction at 25oC under the following...

Consider the following reaction: CO2(g)+CCl4(g)⇌2 COCl2(g). Calculate ΔG for this reaction at 25oC under the following conditions.

PCO2 = 0.115 atm

PCCl4 = 0.185 atm

PCOCl2 =0.755 atm

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Answer #1

ΔGrxn = ΔG°rxn + RTlnQ

ΔGrxn = ΔG°rxn + RTln ( [COCl2]^2 / [CO2] [CCl4])

CO2(g)+CCl4(g)⇌2 COCl2(g)

ΔG°rxn = ΔG°of products - ΔG° of reactants

From the standard ΔG° values;

CO2 (g)= -394.4 kJ/mol
CCl4 (g)= -60.63 kJ/mol
COCl2 (g)= -206.8 kJ/mol

ΔG° = [(2) (-206.80] - [-394.4 & -60.63]
ΔG° = -413.6 - (-455.03)

ΔG° = + 42.43 kJ

Now;

ΔGrxn = ΔG°rxn + RTln ( [COCl2]^2 / [CO2] [CCl4])

ΔGrxn = + 42.43 kJ + (0.008314) (298) ln ( [0.755]2 / [0.115] [0.185])

ΔGrxn = + 42.43 kJ + (0.008314) (298) ln (26.79)

ΔGrxn = + 42.43 kJ + (0.008314) (298) (3.288)

ΔGrxn = + 42.43 kJ + 8.1466

ΔGrxn = +50.5766


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