Question

Consider the following reaction: CO2(g)+CCl4(g)⇌2COCl2(g). Calculate ΔG for this reaction at 25 ∘C under the following...

Consider the following reaction: CO2(g)+CCl4(g)⇌2COCl2(g). Calculate ΔG for this reaction at 25 ∘C under the following conditions. PCO2= 0.120 atm PCCl4= 0.185 atm PCOCl2= 0.750 atm

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Answer #1

I am quessing that this might not be at equilibrium...
at which case dG = 0
we have
ΔGrxn = ΔG°rxn + RTlnQ
using these dGf's
CO2 (g)= -394.4 kJ/mol
CCl4 (g)= -60.63 kJ/mol
COCl2 (g)= -206.8 kJ/mol

we first find the statndard dG for the reaction

dGo = dGf products - reactants
dGo = [(2) (-206.80] - [-394.4 & -60.63]
dGo = -413.6 - (-455.03)

dGo = + 42.43 kJ


now we use
ΔGrxn = ΔG°rxn + RTlnQ

dG = + 42.43 kJ + (0.008314) (298) ln ( [COCl2]^2 / [CO2] [CCl4]


dG = + 42.43 kJ + (0.008314) (298) ln ( [0.750]^2 / [0.120] [0.185]

dG = + 42.43 kJ + (0.008314) (298) ln ( 25.33)

dG = + 42.43 kJ + (2.4776) (3.2322)

dG = + 42.43 kJ + 5.709

dG = 48.13 kJ

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