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elemental analysis: c, 70.57; H, 5.92; O, 23.50

elemental analysis: c, 70.57; H, 5.92; O, 23.50

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Answer #1

Let the total mass of the compound be 100g in which 70.57 g is C, 5.92 g is H and 23.50 g is O

Calculate the number of moles of C, H and O

Number of moles = Mass given / Molecular mass

Number of moles of C = 70.57 / 12.01 = 5.875

Number of moles of H = 5.92 / 1.008 = 5.873

Number of moles of O = 23.50 / 15.99 = 1.469

Divide all the values of number of moles by lowest number of moles

5.875 / 1.469 = 3.9 4

5.873 / 1.469 = 3.9 4

1.469 / 1.469 = 1

Molecular formula comes out to be C4H4O

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