Determine a formula that describes how potential varies between your plates as a function of position. Hint,Φ = kx What is k for your plates? What is its physical significance?
Here is my experimental data. I am at a total loss. Please help!!!
Distance (m) | Potential (V) |
0.01 | 1.39 |
0.02 | 2.6 |
0.03 | 3.8 |
0.04 | 5.93 |
0.05 | 6.7 |
0.06 | 8.36 |
0.07 | 10.1 |
0.08 | 10.3 |
Capacitor
parallel plate capacitor capacitance is
C = epsilon_0*A/x
where epsilon_0 is permitivity of free space , A is area of each plates , x is separation of the plates
and the relation between charge , potential and capacitance of a capacitor is
Q = C*V
V = Q/C
V = Q/(epsilon_0*A/x)
V = Q*x/epsilon_0*A
if the charge and the area of the plates are unchanged then as the distance increases the potential will also increase by
phi = kx , here k = Q/epsilon_0*A
from the data it is clear that as the distance increasing the potential is also increasing
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