Question

A solution is known to contain either Cd2+ ion or [SnCl6]2- ion. Give a two – step procedure that would allow the determination of which ion is present. What would you expect in each step?

Answer 1

As per the given question we need to identify the presence of either ions

Both the ions Cd+2 and Sn+4 are of II group element in the analysis of radicals

(i) On treatment with H2S (with dilute HCl) both the ions will precipitate out as sulphide ion.

However the colour of CdS is bright canary yellow (it distinguish it from other group ions)

(ii) When we add yellow ammonium sulphide to the two precipitate then the sulphide precipitate of SnCl6]-2 will gets dissolved while that of Cd+2 will not dissolve