What is the concentration of the Cu+2 ion, expressed as molarity, in a solution prepared by dissolving 1.25g of CuSO4 * 5H2O in enough water to give 50.0 mL of solution?
mass of CuSO4 * 5H2O = 1.25
moles of CuSO4 * 5H2O = 1.25 / 249.685
= 5.006 x 10^-3 mol
volume = 50.0 mL = 0.050 L
Molarity = moles / volume
= 5.006 x 10^-3 / 0.050
Molarity = 0.100 M
concentration of the Cu+2 ion = 0.100 M
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