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When 14.2 g of Li and 10.3 g of Cl2 react, what is the mass, in...

When 14.2 g of Li and 10.3 g of Cl2 react, what is the mass, in grams, of LiCl that is produced? 2Li(s)+Cl2(g)→2LiCl(s) Express your answer with the appropriate units.

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Homework Answers

Answer #1

The balanced chemical equation is:

2Li + Cl2 ---> 2LiCl

Atomic weight of Li = 6.9 grams

Molecular weight of Cl2 = 71 grams

Hence, 71 grams of Cl2 requires 2 X 6.9 grams of Li

Therefore, applying unitary method,

10.3 grams of Cl2 requires grams of Li = 2.001 grams of Li

Here, the amount of Li given is 14.2 grams. The amount required is only 2.001 grams of Li. Hence, chlorine is the limiting reagent.

Now, Molecular weight of LiCl = (6.9 + 35.5) = 42.4 grams of LiCl

From the given equation,

71 grams of chlorine produces 2 X 42.4 grams of LiCl = 84.8 grams of LiCl

10.3 grams of chlorine produces grams of LiCl = 12.301 grams of LiCl.

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