Consider the dissolution of the slightly soluble salt silver hypochlorite (AgClO) with a Ksp value of 5.7 x 10-12 .
1. Calculate the mass (in grams) that dissolves in 1.00 L of deionized water. (5 pts)
2. Calculate the mass (in grams) that dissolves in 1.00 L of an aqueous solution buffered at pH = 2.15. (10 pts)
3. Calculate the mass (in grams) that dissolves in 1.00 L 0.200 M Na2S2O3 solution (10 pts)
1. AgClO (aq) Ag+ (aq) + ClO- (aq)
Ksp = [Ag+][ClO-] = [C]2
[C] = 5.7 x 10-12 = 2.38 x 10-6 mole/L = 2.38 x10-6 x 159.32 g/L = 0.000379 g/L
b) Aqueous AgClO is basic in nature. So at lower pH, solubility of AgClO will increase according to Le-Chatelier's principle.
c) Ag+ (aq) + 2S2O32- (aq) [Ag(S2O3)2]3- (aq)
So for each mole of Ag+ one requires 2 moles of S2O32-
1 L of 0.2 M S2O32- = 0.2 mole
so moles of Ag+ must be = 0.2/2 = 0.1 mole = 0.1x112 g = 11.2 g of Ag
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