Given the linear regression equation: y=-63.5x-169.94 with R^2 value 0.9924, calculate the value of NaF in the orignal mouthwash sample and the weight percentage of NaF in sample. In this experiment 5.2344 grams of mouthwash was diluted into a 50 mL volumetric flask. eV of mouthwash= 37.6
Dear Student,
Given the linear regression equation: y=-63.5x-169.94
5.2344 grams of mouthwash was diluted into a 50 mL volumetric flask
eV of mouthwash= 37.6
plugged 37.6 in into the eqution, to get
-63.5x=207.54 or x=-3.268
, taking the antilog to obtained 0.0005395 and times it by the volume 0.05 L to get the moles of NaF.
multiply by the molar mass of fluoride, 18.998 g/mol, to get grams of fluoride, 0.000529 g NaF
therefore,
0.000529 g F/ 5.2344g*1000000=86628.3ppm
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