Question

How much heat, in joules and in calories, must be removed from 3.61 mol of water...

How much heat, in joules and in calories, must be removed from 3.61 mol of water to lower its temperature from 23.7 to 11.5°C? Include the sign in your answer.

joules

calories

Science   Chemistry   
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Answer #1

q = msT

mass of water = moles * molarmass

                         = 3.61*18

                        = 64.98 grams

q = - 64.98*4.184*(23.7-11.5)

   = - 3316.89 J

   = - 3.31689 KJ

   = - 792.75 calories

= - 0.79275 Kcalories

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