How many joules heat must be added to 2.0 kg of ice at a temperature of -30 °C to bring it to room temperature 20 °C?
(Specific heat capacity of ice is 2100 J/kg °C).
(Specific heat capacity of water is 4186 J/kg °C).
(Latent heat of water-ice is 3.33x105 J/kg)
Group of answer choices
126.52 kJ
959.44 kJ
4293.44 kJ
668.78 kJ
The temperature of m kg of ice can be raised from -30oC to 0oC by supplying H1 of heat.
dT = 30o ; Sice = 2100
H1 = m Sice dT = 2 x 2100 x 30 = 126000 J
The heat required to change Ice at 0oC to Water at 0oC is H2 = m Lice = 2 x 3.33 x 105 J
H2 = 666000 J
The heat required to rise the temperature of water from 0oC to 20oC is H3 = m Swater dT
dT = 20oC ; Swater = 4186
H3 = 2 x 4186 x 20 = 167440 J
The total heat H = H1 + H2 + H3 = 126000 + 666000 + 167440 = 959440 J = 959.44 kJ
OPTION B
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