Question

How much heat must be removed to make ice at -10 degrees C from 2kg of water at 20 degrees C (The latent heat of fusion for water is.25X10^5 J/kg. The specific heat of water is 4190 J/kg K and for ice is 2090 J/kg K.)

a. 7.95 X10^5

b. 8.37 X10^5

c.8.75 X10^5

d. 2.09x10^5

Answer #1

Specific heat for ice is 2.09 J/gk

Specific heat of water is 4.190 J/gk

1.

latent heat of fusion of water is 0.25x10^{5}

heat to raise the temp of 2000g ice from -10C to 0C

Q = mass ice x specific heat ice x deltaT

=2000x2.09x10 J

=41800J

2) heat to melt 2000g ice at 0C

Q = moles ice x molar heat of fusion

=2x6.03=12.06 kJ

3. heat to raise the temp of 2000g water from 0C to 100C

Q = mass water x specific heat water x deltaT

=2000x4.19x100 J

=8.37x10^{5}

Therefore the answer is option c

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