Question

CuSO4(aq) + Zn(s) → ZnSO4(aq) + Cu(s)

What is the theoretical yield (moles) of Copper for this reaction?

What is the % yield for this reaction?

Mass of zinc used: 2.07 g

Let me know if you need more information to solve.

Answer 1

2.07g grams of zinc corresponds to 0.031 moles (since 1 mole is 65.4 grams)
. If there's a sufficiency of CuSO4, then Zn is the limiting reactant.

Theoretical yield of Cu is mol * molar mass
(since the Cu mol will be the same as the Zn mol)
= 0.031 mol * 63.5 g/mol = 1.968 g.
Actual yield given as x g( you havent mention the yield of copper youo got after calculation .
Percent yield Cu = (x / 77.47) * 100 = y %

i hope now u can calculate by just substiting the value of x of actual yield of copper