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The specific rate constant for the first-order decomposition of N2O5(g) to NO2(g) and O2(g) is 7.48×10−3s−1...

The specific rate constant for the first-order decomposition of N2O5(g) to NO2(g) and O2(g) is 7.48×10−3s−1 at a given temperature.

A. Find the length of time required for the total pressure in a system containing N2O5 at an initial pressure of 0.100 atm to rise to 0.200 atm .

B. Find the total pressure after 110 s of reaction.

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Answer #1

2 N2O5(g) -------------------> 4 NO2(g) + O2(g)

0.1 - 2x                                    4x                x

0.1 - 2x + 4x + x = 0.2

0.1 + 3x = 0.2

x = 0.033

PN2O5 = 0.1 - 2x = 0.034 atm

rate constant k = 7.48×10−3 s-1

k = 1/ t ln (Po / Pt)

7.48×10^−3 = 1 / t ln (0.1 / 0.034)

t = 144 sec.

time required = 144 sec

B)

k = 1 / t ln (Po / Pt)

7.48 x 10^-3 = 1 / 110 ln (0.1 / Pt)

Pt = 0.044 atm

0.1 - 2x = 0.044

x = 0.072

0.1 - 2x + 4x + x = 0.316

total pressure after 110 sec = 0.316 atm

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