How much 100% ethanol would someone need to make 100 mL of a 70% alcohol?
Please show all work. Thanks.
70% alcohol means;
In the 100 mL solution, 70 mL of alcohol and 30 mL of other solvents (water).
So,
70% (100 mL of E) + 30%(100mL of W) = 100 mL (total liquid mixed) [where E = ethanol and W = water].
Therefore, you need:
0.7 x 100 mL = 70 mL of ethanol
0.3 x 100 mL = 30 mL of water
OR
You have to dilute the alchohol solution.
Using the dilution equation,
C1V1=C2V2
70 x 100 = 100 x V2
V2 = 70 ml
You have to take 70 mL from the 100% alcohol solution and add water
until it becomes 100 mL.
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