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How much stock solution would you need to make 50 mL of a 86 mM Potassium...

How much stock solution would you need to make 50 mL of a 86 mM Potassium chloride (KCl) solution, given the stock solution is 1 M?

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Answer #1

Given Data:

Concentration of stock solution (M1) = 1M

Required concentration (M2) = 86 mM

Required volume of solution (V1) = 50 ml

Volume of stock solution required to make 86mM solution (V2) = ?

M1V1 = M2V2

1M x 50 ml = 86mM x V2

V2 = 1 x 50 / 86 = 0.58 ml

The stock solution of 0.58 ml is required to make 50 ml of 86mM KCl solution.

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