1) A heliox deep-sea diving mixture contains 2.0 g of oxygen to every 98.0 g of helium. What is the partial pressure of oxygen when this mixture is delivered at a total pressure of 8.7 atm ?
2) An experiment shows that a 116 mL gas sample has a mass of 0.168 g at a pressure of 694 mmHgand a temperature of 31 ∘C. What is the molar mass of the gas?
3) A sample of gas has a mass of 0.565 g . Its volume is 119 mL at a temperature of 85 ∘C and a pressure of 758 mmHg. Find the molar mass of the gas.
Please answer all parts.
1)
m = 2 g of O2 per m = 98 g of He
P of O2
Pt = 8.7 atm
change all to mol
mol of O" = mass/M" = 2/32 = 0.0625
mol of He = mass/MW = 98/4 = 24.5
total mol 24.5+0.0625 = 25.125mol
mol frac of O2 = 0.0625/25.125 = 0.00248
then
Partial P of O2 = xO2 * PT = 0.00248*8.7 = 0.02157 atm of O2
2)
PV = nRT
n = mass/MW
then
PV = mass/MW*RT
solve for MW
MW = mass*RT/(PV)
P = 694/760 = 0.913157atm
MW = (0.168)(0.082)(31+273)/(0.913157*0.116)
MW = 39.536 g /mol (probably argon)
3)
m = 0.565
V = 119 ml = 0.119 L T = 85 °C = 85+273 = 358 K
P = 758 mm Hg = 758/760 atm = 0.9973 atm
then
PV = nRT
n = m/MW so
PV = m/MW * RT
MW = m*RT/(PV)
MW = (0.565 *0.082)(358 )/(0.9973*0.119) = 139.756 g/mol
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