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Explain how qreaction would be affected if a greater amount of surrounding solvent (water) is used?...

Explain how qreaction would be affected if a greater amount of surrounding solvent (water) is used? Please explain.

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Answer #1

q run would not be affected because it is equal in magnitude of the opposite in sign to the heat lost by the reaction.

                                                         OR

the heat from the chemical reaction(Qrxn) that you are studying is equal to but opposite sign from the value of Qcal.

qrxn= -qcal.

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