Write the alpha-decay of 241Am reaction scheme, what branching ratio of this? (with details)
Alpha decay occurs when the nucleus of an atom spontaneously
ejects an alpha particle. The alpha particle is the same as a
helium nucleus with 2 protons and 2 neutrons. This means the number
of protons in the nucleus is reduced by 2 and the total number of
nucleons is reduced by 4.
241Am95 → ZXA +
4He2
A = number of protons = 95 - 2 = 93
X = the element with atomic number = 93
According to the periodic table, X = neptunium or Np.
The mass number is reduced by 4.
Z = 241 - 4 = 237
Substitute these values into the reaction:
241Am95 → 237Np93 +
4He2
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