Question

Calculate the grams of sodium hydroxide in 750.0 mL of 1.23 M sodium hyroxide.

Answer 1

NaOH- Molecular mass = 40

40 gm of NaOH in 1000 mL = 1M

(40 x 1.23) gm of NaOH in 1000 mL = 1.23 M

   49.2 gm of NaOH in 1000 mL = 1.23 M.

Now,

1000 mL of 1.23 M NaOH contains 49.2 gm.

750 mL of 1.23 M NaOH contains (49.2 x 750)/1000 gm

750 mL of 1.23 M NaOH contains 36.9 gm