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The solubility product constant for Ba(IO3)2 is 1.57x10-9. What is the mass of Ba(IO3)2 (487g/mole) can...

The solubility product constant for Ba(IO3)2 is 1.57x10-9. What is the mass of Ba(IO3)2 (487g/mole) can be dissolved in 500 mL of water at 25C?

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Answer #1

Ba(IO3)2 Ba2+ + 2IO3-

the solubility product of the above reaction can be given as [Ba2+][IO3-]2 = Ksp

lets say solubility is s, then Ksp= [s][2s]2

but given valus of Ksp= 1.57*10-9 = 4s3

thus s3 = (1.57/4) *10-9 = 0.3925 *10-9  

therefore by taking cube root, we get s= 0.732*10-3

so solubility is  0.732*10-3 mole in 1 litre.

therefore in 500 mL (0.5litre) it should have 0.366*10-3 mole .

1 mole = 487 g

0.366*10-3 mole = 0.366*10-3 *487 = 0.178 gram of mass is soluble.

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