Question

The solubility product constant Ksp of Mn(OH)2 is 2.1 x 10-13 at 25oC. The molar mass...

The solubility product constant Ksp of Mn(OH)2 is 2.1 x 10-13 at 25oC. The molar mass of Mn(OH)2 is 88.96 g/mol.

a. Calculate its molar solubility

b. Calulate its solubility in g/L

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Answer #1

Solution.

The chemical equation of solubility:

Mn(OH)2(s) = Mn2+(aq)+2OH-(aq);

The solubility product expression:

Let [Mn2+] = x, then [OH-] = 2x and

Therefore, the molar solubility of Mn(OH)2 is

It corresponds to a solubility (g/L)

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