Question

A block of an alloy of mass 36.0 g and at a temperature of 275.21 K...

A block of an alloy of mass 36.0 g and at a temperature of 275.21 K is placed in a calorimeter containing 34.0 g of water at 366.25 K. If the final temperature of the alloy and water is 324.25 K, calculate the specific heat (in J/g/K) of the metal. The specific heat of water is 4.184 J/g/K. Express your answer to three significant figures in scientific notation.

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Answer #1

Mass of block = 36.0 g

Initial temperature of block = 275.21 K

Mass of water = 34.0 g

Initial temperature of water = 366.25 K

Final temperature of block and water = 324.25 K

Specific heat of water = 4.184 J/g/K

Let the specific heat of alloy be s.

We know that the heat released by water = heat absorbed by the block.

Heat released by water,

q1 = m*c*T

= 34*4.184*(324.25 - 366.25)

= - 5974.752 J

Heat absorbed by block'

q2 = m*s*T

= 36*s*(324.25 - 275.21)

= 1765.44 *s J

Now,

q1 + q2 = 0

- 5974.752 + 1765.44 *s = 0

1765.44 *s = 5974.752

s = 3.38 J/g/K

Hence,

specific heat (in J/g/K) of the metal = 3.38 J/g/K

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