Question

You have 0.084mol of carbon and 0.009mol of tin. From this information, calculate:

1. The number of atoms in each sample.

2. The average mass of one atom of carbon (in grams).

3. The average mass of one atom of tin (in grams).

4. The ratio, average mass of one atom of tin: average mass of one atom of carbon. In theory, what is the correct value of the above ratio?

Answer 1

1) total moles = 0.084+0.009 = 0.093

1 mol has 6.023 x 10^23

Total atoms = 0.093 x 6.023 x 10^23 = 5.6 x 10^22

2) C atom average mass = 12.01 amu = 12.01 x 1.6605 x 10^-24 = 1.994 x 10^ -23 g

3) Tin average mass = 118.71 amu = 118.71 x 1.6605 x 10^-24 g = 1.97 x 10^ -22 g

4) ratio of masses = ( 1.97 x 10^-22) /( 1.994 x 10^-23) = 9.8855

by given quantities , C mass = moles of C x atomic mass of C = 0.084 x 12 = 1.008 g

Tin mass = 0.009 x 118.71 = 1.068 g

ratio of masses from given = ( 1.068/1.008) = 1.06