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Fe(OH)2---------> Fe+2 + (OH)-2
HBr provides H+ ions which will react with the OH-2 to form the hydroxide anion, OH-. This lowers the OH-2 concentration. The equilibrium shifts to the right to replace some of the OH-2- removed, so the solubility of Fe(OH)2 increases.
Fe(NO3)2 provides Fe2+ ions. The equilibrium shifts to the left as the system tries to use up some of the added Fe2+. The solubility of Fe(OH)2 is reduced.
KCl provides Cl- ions. The equilibrium shifts to the left as the system tries to use up some of the added Cl-. The solubility of Fe(OH)2 decreases.
NH3 has no affect on the equilibrium, so the solubility stays
the same.
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