Question

Alkaline earth metals form slightly soluble carbonate salts with a 1:1 cation-to-anion ratio: CaCO3(s)⇌Ca2+(aq)+CO32−(aq) The Ksp for CaCO3 is 4.50×10−9. Calculate the molar solubility, S, of CaCO3.

Answer 1

Dear Student,

Given,

K_sp of CaCO₃ is 4.50 x 10^-9

To find molar solubility of CaCO₃

Solution

CaCO₃   Ca⁺²_(aq) + CO₃^-2_(aq)

                      S                S

Here S = mol / litre is a solubility of CaCO₃

K_sp = S x S

S = K_sp

S = 4.5 x 10^-9

S = 6.7 x 10^-5 M

Therefore, the molar solubility ( S ) of CaCO₃ is 6.7 x 10^-5 M.