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How to I solve for OH , I just cannot get the exponent correct.

How to I solve for OH , I just cannot get the exponent correct.
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Answer #1

pH = -log[H+]

pOH = -log(OH-)

Let assume that if we know the pH or pOH then we can calculate the H+ or OH- concentrations.

If pOH = 4.5 then OH = 10^-pOH

                                 = 10^-4.5

                                 = 3.16*10^-5

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