Question

Assume a container starts with 3.9 x1025 HA particles dissolved in water and none of its...

Assume a container starts with 3.9 x1025 HA particles dissolved in water and none of its conjugate.   Sodium hydroxide is then added to neutralize the acid until the number of HA particles = 8.7x1024.   Write out the chemical equation for the neutralization reaction and calculate the number of A‐ particles that are in the container after the neutralization.

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Answer #1

chemical equation for the neutralization :

HA   +    NaOH    ------------> NaA   + H2O

number of HA particles = 3.9 x 10^25

number of HA particles neutralize = 8.7 x 10^24

HA particels remain = 3.9 x 10^25 - 8.7 x 10^24

                                 = 3.03 x 10^25

number of A- particles present = 3.03 x 10^25

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