Question

I did my calculations but I'm confused about what to answer.

8. Ratio of moles Ag produced to moles of Cu reacted (round to nearest whole number)

I answered: .012 mol Ag / .0028 mol Cu = 4.28

Round to the nearest number = 4

Ratio = 1:4

9.How close is this calculated ratio to that in the balanced equation for this reaction? Explain.

So, the equation is 2AgNO3 + Cu = 2Ag + Cu(NO3)2

Which can be the best answer to this question?

Answer 1

Information provided

moles of Ag = 0.012 mol , moles of Cu = 0.0028 mol

moles of Ag: moles of Cu = 0.012/ 0.0028 = 4.28 = 4 (nearest whole number)

moles of Ag : moles of Cu = 4:1 . So, molar ratio of Ag: Cu = 4:1

The given balanced equation is,

2AgNO3 + Cu ---> 2Ag + Cu(NO3)2 ...............(1)

2 mol 1 mol 2 mol 1 mol

From equation 1, molar ratio of Ag:Cu = 2:1

therefore,calculated molar ratio of Ag:Cu / molar ratio of Ag:Cu(from equation) = 4:1 /2:1 = 2

As a result, calculated molar ratio of Ag:Cu is twice the molar ratio of Ag:Cu(from equation).