Al(NO3)3
1)What is the Hydrolysis Net ionic equation
2)Write the Ka or Kb expression?
3)What is the valuse of the Ka or Kb?
1) Write the complete molecular equation as
Al(NO3)3 (aq) + 3 H2O (l) ---------> Al(OH)3 (s) + 3 HNO3 (aq)
Decompose the aqueous species into ions and write
Al3+ (aq) + 3 NO3- (aq) + 3 H2O (l) ---------> Al(OH)3 (s) + 3 H+ (aq) + 3 NO3- (aq)
Cancel out the common terms and write the net ionic equation as
Al3+ (aq) + 3 H2O (l) --------> Al(OH)3 (aq) + 3 H+ (aq)
2) Al(OH)3 (s) is a base and partially ionizes to produce hydroxide ion as below.
AL(OH)3 (s) <=======> Al3+ (aq) + 3 OH- (aq)
Since OH- is produced, we work with Kb.
Kb = [Al3+][OH-]3
3) The pKa value of Al(OH)3 is reported as 11.2.
It is known that
pKa = -log (Ka)
=====> log (Ka) = -pKa
=====> Ka = antilog (-pKa)
=====> Ka = 6.309*10-12 ≈ 6.31*10-12 (ans).
Get Answers For Free
Most questions answered within 1 hours.