Question

for the reactions A and B in problem #2, write the balanced formula equation, complete ionic equation, and net ionic equation. A) FeSo4+ KCl. B) Al(NO3)3+ Ba(OH)2

Answer 1

a)

Fe+2 and SO4-2 + K+ and Cl-

note that only FeCl2 forms precipitate

so

molecular:

FeSO4(aq) + KCl(aq) --> FeCl2(s) + K2SO4(aq)

Complete net ionic

Fe+2(aq) + SO4-2(aq)+ 2K+(aq) + 2Cl-(aq) --> FeCl2(s)+SO4-2(aq)+ 2K+(aq)

Net ionic

Fe+2(aq) + 2Cl-(aq) --> FeCl2(s)

b)

Al+3 + NO3- and Ba+2 with 2OH-

so

Only Al+3 and OH- form preicpiate

Molecular

2Al(NO3)3 + 3Ba(OH)2 --> 2Al(OH)3(s) + 3Ba(NO3)2(aq)

Molecular

2Al+3(aq) + 6NO3-(aq) + 3Ba+2(aq) + 6OH-(aq) --> Al(OH)3(s)+ 6NO3-(aq) + 3Ba+2(aq)

Net ionic equaton

Al+3(aq) + 3OH-(aq) --> Al(OH)3(s)