Select the compound that has bond angles nearest to 120°.
A. CH4
B. H−C≡C−H
C. CHI3
D. O=C=S
E. H2C=O
1)
C is CH4 is sp3 hybridised.
CH4 is tetrahedral
So, bond angle would be 109.5 degree
B)
triple bonded carbon are sp hybridised and they will be linear
So, bond angle = 180 degree
C)
C is CHI3 is sp3 hybridised.
CH4 is tetrahedral
So, bond angle would be 109.5 degree
D)
central C is sp hybridised and they will be linear
So, bond angle = 180 degree
e)
Central C forms 3 sigma bond and hence it is sp2 hybridised
So, it is trigonal planar.
Bond angle would be 120 degree
Answer: E
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