Question

If you begin with 24.6 mL of 0.224 M HC2H3O2, how many mL of 0.176 M Ba(OH)2 should be added to reach the equivalence point?

Answer 1

we have the Balanced chemical equation as:

2 HC2H3O2 + Ba(OH)2 ---> C2H3O2- + 2 H2O

Here:

M(HC2H3O2)=0.224 M

M(Ba(OH)2)=0.176 M

V(HC2H3O2)=24.6 mL

According to balanced reaction:

1*number of mol of HC2H3O2 =2*number of mol of Ba(OH)2

1*M(HC2H3O2)*V(HC2H3O2) =2*M(Ba(OH)2)*V(Ba(OH)2)

1*0.224 M *24.6 mL = 2*0.176M *V(Ba(OH)2)

V(Ba(OH)2) = 15.7 mL

Answer: 15.7 mL