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Li+1 + e- + C6 --> LiC6 Eo = -2.84 V oxidation Li+1 + e- +...

Li+1 + e- + C6 --> LiC6 Eo = -2.84 V oxidation

Li+1 + e- + CoO2 --> LiCoO2 Eo = +0.25 V reduction

Use the above information to write the complete spontaneous redox reaction that combines the half cell reactions.

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Answer #1

Li+1 + e- + C6 --> LiC6             Eo = -2.84 V oxidation

Li+1 + e- + CoO2 --> LiCoO2 Eo = +0.25 V reduction

LiC6 --------->Li+1 + e- + C6      Eo = 2.84 V oxidation

Li+1 + e- + CoO2 --> LiCoO2    Eo = +0.25 V reduction

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LiC6 + CoO2 -------------> LiCoO2    E0cell = 3.09v

n =1

G0    = -nE0cell*F

             = -1*3.09*96500

             = -298185J

G0 <0 spontaneous reaction

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