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what is the minimum number of moles of potassium permanganate that would require to completly oxidize...

what is the minimum number of moles of potassium permanganate that would require to completly oxidize 1.0 moles of benzaldehyde?

the answer is 0.67...

please show the work for this aswer

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Answer #1

A balanced equation for oxidation of Benzaldehyde by KMnO4 is,

3 ArCOH + 2 KMnO4 + H2SO4 3ArCOOH + 2MnO2 + H2O + K2SO4.

From this stoichiometrically balanced equation, we can write mole equivalence as,

3 moles of ArCOH (benzaldehyde) 2 moles of KMnO4.

On dividing by 3 throughout.

1 mole of ArCOH (benzaldehyde) 2/3 mole of KMnO4.

1 mole of ArCOH (benzaldehyde) 0.67 mole of KMnO4.

Hence the answer.

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