What is the maximum theoretical number of moles of aluminum oxide that can be recovered from the reaction of 27.7 mol of aluminum and 27.8 moles of oxygen gas?
4 Al (s) + 3 O2(g) → 2 Al2O3(s)
What mass of aluminum oxide can be recovered from the complete reaction of 34.3 g of Al with 34.3 g of oxygen gas?
4 Al (s) + 3 O2(g) → 2 Al2O3(s)
If 8.7 moles of Al and 3.2 moles of Fe2O3 are allowed to react completely, how many moles of the excess reactant will remain? (Please give your answer with one decimal place even if one of the initial values does not show any decimal places.)
2Al + Fe2O3 → Al2O3 + 2Fe
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