How many grams of water in a 6.0 m HCl solution contains 0.25 grams of HCl?
Molar mass of HCl,
MM = 1*MM(H) + 1*MM(Cl)
= 1*1.008 + 1*35.45
= 36.458 g/mol
mass(HCl)= 0.25 g
we have below equation to be used:
number of mol of HCl,
n = mass of HCl/molar mass of HCl
=(0.25 g)/(36.458 g/mol)
= 6.857*10^-3 mol
molality = number of mol of HCl / mass of water in Kg
6.0 = 6.857*10^-3 / mass of water in Kg
mass of water in Kg = 1.143*10^-3 Kg
mass of water = 1.1 g
Answer: 1.1 g
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