Question

Write electron configurations for each of the following ions.

V3+ Mo3+  

Answer 1

1)

Number of electron in V = 23

Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d3 4s2

Since charge on V is +3

So, we need to remove 3 electrons

Electrons are always removed from highest number orbital

Removing 2 electron from 4s

Removing 1 electron from 3d

Final electronic configuration is : 1s2 2s2 2p6 3s2 3p6 3d2

Answer: 1s2 2s2 2p6 3s2 3p6 3d2

2)

Number of electron in Mo = 42

Electronic configuration is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d5 5s1

Since charge on Mo is +3

So, we need to remove 3 electrons

Electrons are always removed from highest number orbital

Removing 1 electron from 5s

Removing 2 electron from 4d

Final electronic configuration is : 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d3

Answer: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d3