Write electron configurations for each of the following ions.
V3+ Mo3+
1)
Number of electron in V = 23
Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d3 4s2
Since charge on V is +3
So, we need to remove 3 electrons
Electrons are always removed from highest number orbital
Removing 2 electron from 4s
Removing 1 electron from 3d
Final electronic configuration is : 1s2 2s2 2p6 3s2 3p6 3d2
Answer: 1s2 2s2 2p6 3s2 3p6 3d2
2)
Number of electron in Mo = 42
Electronic configuration is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d5 5s1
Since charge on Mo is +3
So, we need to remove 3 electrons
Electrons are always removed from highest number orbital
Removing 1 electron from 5s
Removing 2 electron from 4d
Final electronic configuration is : 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d3
Answer: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d3
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