What is the entropy change associated with the following reaction?
Al2O3(s) + 3 H2(g) → 2 Al(s) + 3 H2O(g)
S° (J/mol∙K) 51.00 130.58 28.32 188.83
we have:
Sof(Al2O3(s)) = 51.0 J/mol.K
Sof(H2(g)) = 130.58 J/mol.K
Sof(Al(s)) = 28.32 J/mol.K
Sof(H2O(g)) = 188.83 J/mol.K
we have the Balanced chemical equation as:
Al2O3(s) + 3 H2(g) ---> 2 Al(s) + 3 H2O(g)
deltaSo rxn = 2*Sof(Al(s)) + 3*Sof(H2O(g)) - 1*Sof( Al2O3(s)) - 3*Sof(H2(g))
deltaSo rxn = 2*(28.32) + 3*(188.83) - 1*(51.0) - 3*(130.58)
deltaSo rxn = 180.39 J/mol.K
Answer: 180.39 J/mol.K
Get Answers For Free
Most questions answered within 1 hours.