Question

Calculate the change in entropy (in J/K) for the following reaction at 298 K: C(s) +...


Calculate the change in entropy (in J/K) for the following reaction at 298 K:

C(s) + H2O(g) → CO(g) + H2(g)

Use entropy for graphite (diamond is too expensive).

Notice that the entropy of the solid is much smaller than the entropy of the gases!

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Homework Answers

Answer #1

we have:

Sof(C(s,graphite)) = 5.74 J/mol.K

Sof(H2O(g)) = 188.825 J/mol.K

Sof(CO(g)) = 197.674 J/mol.K

Sof(H2(g)) = 130.684 J/mol.K

we have the Balanced chemical equation as:

C(s,graphite) + H2O(g) ---> CO(g) + H2(g)

deltaSo rxn = 1*Sof(CO(g)) + 1*Sof(H2(g)) - 1*Sof( C(s,graphite)) - 1*Sof(H2O(g))

deltaSo rxn = 1*(197.674) + 1*(130.684) - 1*(5.74) - 1*(188.825)

deltaSo rxn = 133.8 J/K

Answer: 133.8 J/K

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