Solution :-
Delta H vap = 41.12 kJ/ mol * (1000 J / 1kJ) = 41120 J/mol
Normal boiling point = 170.1 C + 273.15 = 443.25 K
Molar entropy of vaporization (delta S vap ) = ?
Delta S vap = Delta H vap / T
= 41120 J per mol / 443.25 K
= 92.8 J/mol K
So molar entropy of vaporization is 92.8 J/mol K
Get Answers For Free
Most questions answered within 1 hours.