Question:For water ∆H°vap = 40.7 kJ/mol at 100.°C, its boiling point.
Calculate w and ∆E for...
Question
For water ∆H°vap = 40.7 kJ/mol at 100.°C, its boiling point.
Calculate w and ∆E for...
For water ∆H°vap = 40.7 kJ/mol at 100.°C, its boiling point.
Calculate w and ∆E for the vaporization of 1.00 mol water at 100.°C
and 1.00 atm pressure.