Question

Phenol (C₆H₅OH) reacts with methyl iodide in the presence of sodium hydroxide to give A (C₇H₈O). A reacts with bromine to give an isomeric mixture B (C₇H₇BrO). Draw the structure of B.

Answer 1

Solution :-

Reaction steps and the strucutre of the B are shown in the following image

In the first step phenol in presence of sodium hydroxide reacts with methyl iodide to form the product A that methoxybenzene.

Then in the next step A reacts with the Br2 and gives product B which is isomeric

A reacts with Br2 to given electrophilic substition products. OCH3 is the ring activating group therefore the Br may get added to the ortho or para position.

Both products are shoiwn in the above image.