Question

Can Pb2+ (aq) oxidize Al(s)? Can Pb2+ (aq) oxidize Cu (s)? Demonstrate each answer.

Can Pb2+ (aq) oxidize Al(s)? Can Pb2+ (aq) oxidize Cu (s)? Demonstrate each answer.

Homework Answers

Answer #1

lead is more reactive than copper but less reactive than aluminium .since in the activity series Al occupies top position than lead followed by copper

according to that the metal present in the top of the series can reduce the bottom elements and oxide itself . in the same way the metal present in the bottom of series can oxidise the upper metals but notthe bottom metals in activity series.

hence lead oxidises aluminium but not copper . while oxidising aluminium ,lead itself undergo reduction

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Consider the following half-reactions: Ag+ (aq) + e- --> Ag(s) E cell = 0.80 VV Cu2+(aq)...
Consider the following half-reactions: Ag+ (aq) + e- --> Ag(s) E cell = 0.80 VV Cu2+(aq) + 2e- --> Cu(s) E cell = 0.34 V Pb2+(aq) + 2e- --> Pb(s) E cell = -0.13 V Fe2+(aq) + 2e- --> Fe(s) E cell = -0.44 V Al3+ (aq) + 3e- --> Al(s) E cell = -1.66 V Which of the above metals or metal ions will oxidize Pb(s)? a. Ag+(aq) and Cu2_(aq) b. Ag(s) and Cu(s) c. Fe2+(aq) and Al3+(aq) d....
Half-reaction E° (V) I2(s) + 2e- -----> 2I-(aq) 0.535V Cu2+(aq) + 2e- -----> Cu(s) 0.337V Cr3+(aq)...
Half-reaction E° (V) I2(s) + 2e- -----> 2I-(aq) 0.535V Cu2+(aq) + 2e- -----> Cu(s) 0.337V Cr3+(aq) + 3e- -----> Cr(s) -0.740V (1) The strongest oxidizing agent is: _____enter formula (2) The weakest oxidizing agent is: _____ (3) The weakest reducing agent is: _____ (4) The strongest reducing agent is: _____ (5) Will Cr3+(aq) oxidize I-(aq) to I2(s)? _____(yes)(no) (6) Which species can be reduced by Cu(s)? _____ If none, leave box blank.
Which metal cation can oxidize Fe(s) to Fe2+(aq) (i.e. which metal cation is a stronger oxidizing...
Which metal cation can oxidize Fe(s) to Fe2+(aq) (i.e. which metal cation is a stronger oxidizing agent)? (A) Al3+ (B) Ag+ (C) Mn2+ (D) Zn2+ Some relevant standard reduction potentials: Ag+(aq) + e- → Ag (s) Eo= +0.80 V Fe2+(aq) + 2e- → Fe (s)    Eo= -0.45 V Zn2+(aq) + 2e- → Zn(s)    Eo= -0.76 V Mn2+(aq) + 2e- → Mn (s)    Eo= - 1.18 V Al3+(aq) + 3e- →Al(s) Eo= -1.66 V
Based on the following information: mass of Al is .91g, mass of Cu is 3.55g, and...
Based on the following information: mass of Al is .91g, mass of Cu is 3.55g, and volume of 1 M CuSO4 is 105 mL What is the theoretical yield of Cu in moles, the theoretical yield of Cu in grams, the actual yield of Cu in grams, the percent yield of Cu, moles of CuSO4, moles of Al, moles Cu product based on starting CuSO4, and the moles Cu product based on starting Al. Balanced Equation: 2AL(s) + 3CuSO4(aq) à...
Calculate the standard cell potential for each of the electrochemical cells. Part A 2Ag+(aq)+Pb(s)?2Ag(s)+Pb2+(aq) Express your...
Calculate the standard cell potential for each of the electrochemical cells. Part A 2Ag+(aq)+Pb(s)?2Ag(s)+Pb2+(aq) Express your answer using two significant figures. Part B 2ClO2(g)+2I?(aq)?2ClO?2(aq)+I2(s) Express your answer using two significant figures. Part C O2(g)+4H+(aq)+2Zn(s)?2H2O(l)+2Zn2+(aq)
The cations Pb2+(aq) and Ba2+(aq) can be precipitated as almost insoluble sulfates. The Ksp values for...
The cations Pb2+(aq) and Ba2+(aq) can be precipitated as almost insoluble sulfates. The Ksp values for PbSO4(s) and BaSO4(s) are 2.5 × 10−8 and 1.1 × 10−10, respectively. If you have a solution that is 0.010 mol L-1 in both Pb2+(aq) and Ba2+(aq) ions, and the concentration of SO42-(aq) ions is gradually increased, the less soluble salt will precipitate first. What is the concentration of the cation (Pb2+ or Ba2+) that precipitates first remains in solution just before the second...
Balance Al(s) + MnO4^- (aq) --> MnO2 (s) + Al(OH)4^- (aq) in aqueous basic solution
Balance Al(s) + MnO4^- (aq) --> MnO2 (s) + Al(OH)4^- (aq) in aqueous basic solution
Write the complete equation and net ionic equation for the following: Al(s)+Fe(NO3)3--------------> Al(s)+Cu(NO3)2--------------> Al(s)+Zn(NO3)2--------------> Al(s)+ZnCl4-------------->
Write the complete equation and net ionic equation for the following: Al(s)+Fe(NO3)3--------------> Al(s)+Cu(NO3)2--------------> Al(s)+Zn(NO3)2--------------> Al(s)+ZnCl4-------------->
1) Cu(S) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l) 2) 2HNO3(aq) + Na2CO3(s) -> H2O(l)...
1) Cu(S) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l) 2) 2HNO3(aq) + Na2CO3(s) -> H2O(l) + CO2(g) + 2NaNO3(aq) 3)Cu(NO3)2(aq) + Na2CO3(s) -> CuCO3(s) + 2NANO3(aq) 4)CuCO3(s) + 2HCL(aq) -> CuCl2(aq) + H2O(l) + CO2(g) 5)CuCl2(aq) + Cu(s) -> 2CuCl(s) weight of copper 1.022g volume of added nitric acid   5.3 ml total weight of added sodium carbonate 4.873g weight of watch glass and filter paper 25.372g Weight of watch glass, filter paper, and CuCl precipitate 53.650 g What is...
Lead ions can be precipitated from solution with KClaccording to the following reaction: Pb2+(aq)+2KCl(aq)→PbCl2(s)+2K+(aq) When 28.8...
Lead ions can be precipitated from solution with KClaccording to the following reaction: Pb2+(aq)+2KCl(aq)→PbCl2(s)+2K+(aq) When 28.8 g KCl is added to a solution containing 25.7 gPb2+, a PbCl2 precipitate forms. The precipitate is filtered and dried and found to have a mass of 29.1 g . 1. Determine the limiting reactant (Pb2+ or KCL) 2. Determine theoretical yield of PbCl2 3. Determine percent yield for the reaction
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT