Question

1) Cu(S) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l) 2) 2HNO3(aq) + Na2CO3(s) -> H2O(l)...

1) Cu(S) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)

2) 2HNO3(aq) + Na2CO3(s) -> H2O(l) + CO2(g) + 2NaNO3(aq)

3)Cu(NO3)2(aq) + Na2CO3(s) -> CuCO3(s) + 2NANO3(aq)

4)CuCO3(s) + 2HCL(aq) -> CuCl2(aq) + H2O(l) + CO2(g)

5)CuCl2(aq) + Cu(s) -> 2CuCl(s)

weight of copper 1.022g

volume of added nitric acid   5.3 ml

total weight of added sodium carbonate 4.873g

weight of watch glass and filter paper 25.372g

Weight of watch glass, filter paper, and CuCl precipitate 53.650 g

What is the .....?

1. Experimental yield of CuCl?

2. Theoretical yeild of CuCl?

3. percent yield of CuCl?

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Answer #1

Cu + 4HNO3 Cu(NO3)2 + 2NO2 + 2H2O

1.022 g Cu = 0.0161 mol Cu

5.3 mL HNO3 = 8.003 g HNO3 = 0.1270 mol HNO3

1 mol Cu(NO3)2 x 0.0161 mol Cu = 0.0161 mol Cu(NO3)2

1 mol Cu

4.873 g Na2CO3 = 0.0459 mol Na2CO3

Cu(NO3)2 + Na2CO3 CuCO3 + 2NaNO3

1 mol CuCO3 x 0.0161mol Cu(NO3)2 = 0.0161 mol CuCO3

1 mol Cu(NO3)2

CuCO3 + 2HCl CuCl2 + H2O + CO2

  1 mol CuCl2   x 0.0161 mol CuCO3 = 0.0161 mol CuCl2

1 mol CuCO3

CuCl2 + Cu 2CuCl

  2 mol CuCl x 0.0161 mol CuCl2 = 0.0322 mol CuCl

1 mol CuCl2

0.0322 mol CuCl = 3.1878 g CuCl

1) Experimental yield of CuCl = 5.3650 g - 2.5372 g = 2.8278 g CuCl

2) Theoretical yield of CuCl = 3.1878 g CuCl

3) % Yield of CuCl = 2.8278 g x 100 / 3.1878 g = 88.71%

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